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Welcome! The problems shown below should be worked on **on
paper**, since the quizzes and exams you take in this course will
also be on paper. You do not need to submit your solutions anywhere.

We encourage you to complete this worksheet in groups during an
extra practice session on Friday, January 12. Solutions will be posted
after all sessions have finished. This problem set is not designed to
take any particular amount of time - focus on understanding concepts,
not on getting through all the questions.

`prices`

is an array of prices, in dollars, of different
products at the grocery store. Similarly, `calories`

is an
array of the calories in these same products, in the same order.

What does `type(prices[0])`

evaluate to?

`int`

`float`

`str`

The price of the first product.

**Answer:** `float`

`prices[0]`

represents the price in dollars of some
product at the grocery store. The data type should be a
`float`

because prices are numbers but not necessarily
integers.

What does `type(calories[0])`

evaluate to?

`int`

`float`

`str`

The calories in the first product.

**Answer:** `int`

Similarly, `calories[0]`

represents the calories in some
product at the grocery store. The data type should be `int`

because calories in foods are always reported as integers.

When we divide two arrays of the same length, their corresponding
elements get divided, and the result is a new array of the same length
as the two originals. In one sentence, interpret the meaning of
`min(prices / calories)`

.

**Answer:** This is the cost per calorie of the product
which has the lowest cost per calorie, which you might say is the
cheapest food to fuel up on (like instant ramen or pasta).

True or False: `min(prices / calories)`

is the same as
`max(calories / price)`

.

**Answer:** False

The former is measured in dollars per calories (a very small number), whereas the latter is measured in calories per dollar (a very big number).

However, there is a connection between these two values. The product
that has the lowest price per calorie is the same product with the most
calories per dollar. So these numbers refer to the same grocery store
product, and we can convert one value into the other by taking the
reciprocal, which swaps the numerator and denominator of a fraction.
Therefore, it’s true that `min(prices / calories)`

is the
same as `1 / max(calories / price)`

.

Suppose we have imported the `math`

module using
`import math`

. Consider the nested expression below:

`int(math.sqrt(math.pow(4 * 2 ** 4, min(9 % 4, 9 / 4, 9 - 4))))`

How many function calls are there in this expression? How many arguments does each function have?

**Answer:** 4 function calls: one argument for
`int()`

, one for `math.sqrt()`

, two for
`math.pow()`

, three for `min()`

.

There are four function calls. One is a call to the type-conversion
function `int()`

, which takes one argument. Another is a call
to `math.sqrt()`

, which takes one argument. Another is a call
to `math.pow()`

, which takes two arguments. Finally is a call
to the built-in function `min()`

, which in this case takes
three arguments, but generally can take two or more arguments.

What does this expression evaluate to?

**Answer:** 8

For nested evaluation, it is helpful to work from the inside out.
Let’s evaluate some arithmetic expressions first. `9 % 4`

evaluates to `1`

because when we divide `9`

by
`4`

, there is a remainder of `1`

. Additionally,
`9 / 4`

evaluate to `2.25`

, and `9 - 4`

evaluates to `5`

. Starting with the inner most function call,
we see `min(9 % 4, 9 / 4, 9 - 4)`

is equiavlent to
`min(1, 2.25, 5)`

which evaluates to `1`

.

The next-most inner function call is the call to
`math.pow()`

which takes two arguments: a number for the
base, and a number for the exponent. We’ve already evaluated the
exponent, but we need to evaluate the base of `4 * 2 ** 4`

.
Using the order of operations, we know we need to evaluate the exponent
first. So `4 * 2 ** 4`

is equivalent to `4 * 16`

or `64`

.

Therefore,
`math.pow(4 * 2 ** 4, min(9 % 4, 9 / 4, 9 - 4))`

simplifies
to `math.pow(64, 1)`

, which Python evaluates to be
`64.0`

, a `float`

.

Next, `math.sqrt(64.0)`

evaluates to `8.0`

.
Finally, the type conversion function `int(8.0)`

evaluates to
`8`

.

After a trip to the zoo, Anthony wrote the following block of code.

```
= 5
zebra = 4
lion = 1
cow = zebra * 2
zebra = abs(cow - lion)
lion = zebra + lion ** 2
zebra = (zebra + lion) / 2 * lion cow
```

After running the above block of code, what is the value of
`cow`

?

**Answer**: `33.0`

The average score on this problem was 60%.

Consider the following four assignment statements.

```
= "5"
bass = 2
tuna = ["4.0", 5, 12.5, -10, "2023"]
sword = [4, "6", "CSE", "doc"] gold
```

What is the value of the expression `bass * tuna`

?

**Answer**: `"55"`

The average score on this problem was 48%.

Which of the following expressions results in an error?

`int(sword[0])`

`float(sword[1])`

`int(sword[2])`

`int(sword[3])`

`float(sword[4])`

**Answer**: `int(sword[0])`

The average score on this problem was 51%.

Which of the following expressions evaluates to
`"DSC10"`

?

`gold[3].replace("o", "s").title() + str(gold[0] + gold[1])`

`gold[3].replace("o", "s").upper() + str(gold[0] + int(gold[1]))`

`gold[3].replace("o", "s").upper() + str(gold[1] + int(gold[0]))`

`gold[3].replace("o", "s").title() + str(gold[0] + int(gold[1]))`

**Answer**:
`gold[3].replace("o", "s").upper() + str(gold[0] + int(gold[1]))`

The average score on this problem was 92%.